b^2+7b+2=-10

Solution for b^2+7b+2=-10 equation:

Simplifying
b2 + 7b + 2 = -10

Reorder the terms:
2 + 7b + b2 = -10

Solving
2 + 7b + b2 = -10

Solving for variable 'b'.

Reorder the terms:
2 + 10 + 7b + b2 = -10 + 10

Combine like terms: 2 + 10 = 12
12 + 7b + b2 = -10 + 10

Combine like terms: -10 + 10 = 0
12 + 7b + b2 = 0

Factor a trinomial.
(4 + b)(3 + b) = 0

Subproblem 1
Set the factor '(4 + b)' equal to zero and attempt to solve:

Simplifying
4 + b = 0

Solving
4 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + b = 0 + -4

Combine like terms: 4 + -4 = 0
0 + b = 0 + -4
b = 0 + -4

Combine like terms: 0 + -4 = -4
b = -4

Simplifying
b = -4
Subproblem 2
Set the factor '(3 + b)' equal to zero and attempt to solve:

Simplifying
3 + b = 0

Solving
3 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + b = 0 + -3

Combine like terms: 3 + -3 = 0
0 + b = 0 + -3
b = 0 + -3

Combine like terms: 0 + -3 = -3
b = -3

Simplifying
b = -3
Solution
b = {-4, -3}